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7n^2+2407n-45594=0
a = 7; b = 2407; c = -45594;
Δ = b2-4ac
Δ = 24072-4·7·(-45594)
Δ = 7070281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7070281}=2659$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2407)-2659}{2*7}=\frac{-5066}{14} =-361+6/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2407)+2659}{2*7}=\frac{252}{14} =18 $
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